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The length and the breadth of a rectangu...

The length and the breadth of a rectangular field are in the ratio 5:4 and its area is 3380 `m^(2)`. Find the cost of fencing it at the rate of Rs. 75 per m.

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To solve the problem step by step, we will follow these steps: ### Step 1: Set up the ratio The length (L) and breadth (B) of the rectangular field are in the ratio of 5:4. We can express this as: - Length = 5x - Breadth = 4x ### Step 2: Use the area formula The area (A) of a rectangle is given by the formula: \[ A = \text{Length} \times \text{Breadth} \] Substituting the expressions for length and breadth, we have: \[ A = (5x) \times (4x) = 20x^2 \] ### Step 3: Set up the equation with the given area We know the area of the field is 3380 m², so we can set up the equation: \[ 20x^2 = 3380 \] ### Step 4: Solve for x² To find \( x^2 \), divide both sides of the equation by 20: \[ x^2 = \frac{3380}{20} \] \[ x^2 = 169 \] ### Step 5: Solve for x Now, take the square root of both sides to find x: \[ x = \sqrt{169} \] \[ x = 13 \] ### Step 6: Find the length and breadth Now that we have the value of x, we can find the length and breadth: - Length = \( 5x = 5 \times 13 = 65 \) meters - Breadth = \( 4x = 4 \times 13 = 52 \) meters ### Step 7: Calculate the perimeter The perimeter (P) of a rectangle is given by the formula: \[ P = 2 \times (\text{Length} + \text{Breadth}) \] Substituting the values we found: \[ P = 2 \times (65 + 52) \] \[ P = 2 \times 117 \] \[ P = 234 \] meters ### Step 8: Calculate the cost of fencing The cost of fencing is given at the rate of Rs. 75 per meter. Therefore, the total cost (C) can be calculated as: \[ C = \text{Perimeter} \times \text{Cost per meter} \] \[ C = 234 \times 75 \] \[ C = 17550 \] Rs. ### Final Answer The cost of fencing the rectangular field is Rs. 17550. ---
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ICSE-AREA OF A TRAPEZIUM AND A POLYGON-EXERCISE 20(B)
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  3. The diagonal of a rectangle is 34 cm. If its breadth is 16 cm, find i...

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  4. The area of a small rectangular plot is 84 m^(2) If the difference b...

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  5. The perimeter of a square is 36 cm, find its area.

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  6. Find the perimeter of a square whose area is 1.69 m^(2) .

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  7. The diagonal of a square is 12 cm long, find its area and length of o...

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  8. The diagonal of a square is 15 m, find the length of its one side and...

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  9. The area of a square is 169 cm^(2). Find its : (i) one side (ii) pe...

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  10. The length of a rectangle is 16 cm and its perimeter is equal to the ...

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  11. The perimeter of a square is numerically equal to its area. Find its ...

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  12. Each side of a rectangle is doubled. Find the ratio between : (i) ...

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  13. In each of the following cases ABCD is a square and PQRS is a rectang...

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  14. A path of uniform width, 3 m, runs around the outside of a square fie...

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  15. A path of uniform width, 2.5 m, runs around the inside of a rectangul...

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  16. The length of a hall is 18 m and its width is 13.5 m. Find the least ...

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  17. A rectangular field is 30 m in length and 22 m in width. Two mutually...

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  18. The length and the breadth of a rectangular field are in the ratio 5:4...

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  19. The length and the breadth of a conference hall are in the ratio 7:4 a...

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