Home
Class 8
MATHS
The length and the breadth of a conferen...

The length and the breadth of a conference hall are in the ratio `7:4` and its perimeter is 110m. Find:
(i) are of the floor of the hall.
(ii) number of tiles, each of rectangle of size `25 cm xx 20 cm`, required for flooring of the hall.
(iii) the cost of the tiles at the rate of Rs. 1,400 per hundred tiles.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the instructions provided in the video transcript. ### Step 1: Determine the Length and Breadth Given that the length (L) and breadth (B) of the conference hall are in the ratio of 7:4, we can express them as: - Length (L) = 7x - Breadth (B) = 4x The perimeter (P) of a rectangle is given by the formula: \[ P = 2(L + B) \] Given that the perimeter is 110 m, we can set up the equation: \[ 2(7x + 4x) = 110 \] ### Step 2: Solve for x Simplifying the equation: \[ 2(11x) = 110 \] \[ 22x = 110 \] Now, divide both sides by 22: \[ x = \frac{110}{22} = 5 \] ### Step 3: Calculate Length and Breadth Now that we have the value of x, we can find the length and breadth: - Length (L) = 7x = 7 * 5 = 35 m - Breadth (B) = 4x = 4 * 5 = 20 m ### Step 4: Calculate the Area of the Conference Hall The area (A) of the rectangle is given by: \[ A = L \times B \] Substituting the values we found: \[ A = 35 \times 20 = 700 \, m^2 \] ### Step 5: Calculate the Number of Tiles Required Each tile has dimensions of 25 cm x 20 cm. First, we need to convert the area of the hall from square meters to square centimeters: \[ 1 \, m^2 = 10,000 \, cm^2 \] So, \[ 700 \, m^2 = 700 \times 10,000 \, cm^2 = 7,000,000 \, cm^2 \] Now, calculate the area of one tile: \[ \text{Area of one tile} = 25 \, cm \times 20 \, cm = 500 \, cm^2 \] Now, we can find the number of tiles (N) required: \[ N = \frac{\text{Total Area}}{\text{Area of one tile}} = \frac{7,000,000 \, cm^2}{500 \, cm^2} = 14,000 \] ### Step 6: Calculate the Cost of the Tiles The cost of tiles is given as Rs. 1,400 for 100 tiles. First, find the cost of one tile: \[ \text{Cost of one tile} = \frac{1400}{100} = 14 \, Rs \] Now, calculate the total cost for 14,000 tiles: \[ \text{Total Cost} = 14,000 \times 14 = 196,000 \, Rs \] ### Final Answers: (i) Area of the floor of the hall = 700 m² (ii) Number of tiles required = 14,000 (iii) Cost of the tiles = Rs. 196,000 ---
Promotional Banner

Topper's Solved these Questions

  • AREA OF A TRAPEZIUM AND A POLYGON

    ICSE|Exercise EXERCISE 20(C )|14 Videos
  • AREA OF A TRAPEZIUM AND A POLYGON

    ICSE|Exercise EXERCISE 20(D)|21 Videos
  • AREA OF A TRAPEZIUM AND A POLYGON

    ICSE|Exercise EXERCISE 20(A)|16 Videos
  • ALGEBRAIC EXPRESSIONS

    ICSE|Exercise Exercise 11(E)|15 Videos
  • CONSTRUCTION (USING RULER AND COMPASSES ONLY)

    ICSE|Exercise EXERCISE 18(D)|10 Videos

Similar Questions

Explore conceptually related problems

The length and the breadth of a rectangular field are in the ratio 5:4 and its area is 3380 m^(2) . Find the cost of fencing it at the rate of Rs. 75 per m.

A wall 4.84\ m long and 3.1\ m high is covered with rectangular tiles of size 22\ c m by 10\ c m . Find the total cost of the tiles at the rate of Rs. 1.50 per tile.

A room is 9.68 m long and 6.2 m wide. Its floor is to be covered with rectangular tiles of size 22 cm by 10 cm. Find the total cost of the tiles at the rate of Rs 2.50 per tile.

The length and breadth of a park are in the ratio 2:1 and its perimeter is 240 m. a path of 2 m wide runs inside it, along boundary. Find the cost of paving the path at Rs.3 per m^2 .

The sides of triangular field ojne in the ratio 5:3:4 and its perimeter is 180m. Find: (i) Its area (ii) Altitude of the triangle corresponding to its largest side. (iii) The cost of levelling the field at the rate of Rs. 10 per square metre.

The length of a hall is 18 m and its width is 13.5 m. Find the least number of square tiles, each of side 25 cm, required to cover the floor of the hall, (i) without leaving any margin. (ii) leaving a margin of width 1.5 m all around. In each case, find the cost of the tiles required at the rate of Rs. 6 per tile.

A marble tile measures 10 c m xx 12 c m How many tiles will be required to cover a wall of size 3 m xx 4 m ? Also, find the total cost of the tiles at the rate of Rs 2 per tile.

Find the area of a rectangle whose length is 5 m more than 4 times its breadth, and its perimeter is 60cm.

A marble tile measures 10 c m xx 12 c m . How many tiles will be required to cover a wall of size 3 m xx 4 m ? Also, find the total cost of the tiles at the rate of Rs 2 per tile.

The floor of a rectangular hall is to be covered with a carpet 150cm wide. If the length and breadth of the hall are 20m and 18m, respectively, find the cost of the carpet at the rate of Rs. 10 per metre.

ICSE-AREA OF A TRAPEZIUM AND A POLYGON-EXERCISE 20(B)
  1. Find the length and perimeter of a rectangle, whose area = 120 cm^(2)...

    Text Solution

    |

  2. The perimeter of a rectangle is 46 m and its length is 15 m. Find its...

    Text Solution

    |

  3. The diagonal of a rectangle is 34 cm. If its breadth is 16 cm, find i...

    Text Solution

    |

  4. The area of a small rectangular plot is 84 m^(2) If the difference b...

    Text Solution

    |

  5. The perimeter of a square is 36 cm, find its area.

    Text Solution

    |

  6. Find the perimeter of a square whose area is 1.69 m^(2) .

    Text Solution

    |

  7. The diagonal of a square is 12 cm long, find its area and length of o...

    Text Solution

    |

  8. The diagonal of a square is 15 m, find the length of its one side and...

    Text Solution

    |

  9. The area of a square is 169 cm^(2). Find its : (i) one side (ii) pe...

    Text Solution

    |

  10. The length of a rectangle is 16 cm and its perimeter is equal to the ...

    Text Solution

    |

  11. The perimeter of a square is numerically equal to its area. Find its ...

    Text Solution

    |

  12. Each side of a rectangle is doubled. Find the ratio between : (i) ...

    Text Solution

    |

  13. In each of the following cases ABCD is a square and PQRS is a rectang...

    Text Solution

    |

  14. A path of uniform width, 3 m, runs around the outside of a square fie...

    Text Solution

    |

  15. A path of uniform width, 2.5 m, runs around the inside of a rectangul...

    Text Solution

    |

  16. The length of a hall is 18 m and its width is 13.5 m. Find the least ...

    Text Solution

    |

  17. A rectangular field is 30 m in length and 22 m in width. Two mutually...

    Text Solution

    |

  18. The length and the breadth of a rectangular field are in the ratio 5:4...

    Text Solution

    |

  19. The length and the breadth of a conference hall are in the ratio 7:4 a...

    Text Solution

    |