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A circular field of radius 105 m has a c...

A circular field of radius 105 m has a circular path of uniform width of 5 m along and inside its boundary. Find the area of the path.

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To find the area of the circular path inside the circular field, we can follow these steps: ### Step 1: Identify the radii - The radius of the outer circular field (C1) is given as \( r_1 = 105 \) m. - The width of the path is \( 5 \) m, so the radius of the inner circle (C2) is: \[ r_2 = r_1 - 5 = 105 - 5 = 100 \text{ m} \] ### Step 2: Calculate the area of the outer circle (C1) - The area of a circle is calculated using the formula: \[ \text{Area} = \pi r^2 \] - Therefore, the area of the outer circle (C1) is: \[ \text{Area of C1} = \pi r_1^2 = \pi (105)^2 = \pi \times 11025 \] ### Step 3: Calculate the area of the inner circle (C2) - Similarly, the area of the inner circle (C2) is: \[ \text{Area of C2} = \pi r_2^2 = \pi (100)^2 = \pi \times 10000 \] ### Step 4: Find the area of the path - The area of the path is the difference between the area of the outer circle and the area of the inner circle: \[ \text{Area of the path} = \text{Area of C1} - \text{Area of C2} \] - Substituting the areas we calculated: \[ \text{Area of the path} = \pi (11025 - 10000) = \pi \times 1025 \] ### Step 5: Substitute the value of \(\pi\) - Using \(\pi \approx \frac{22}{7}\): \[ \text{Area of the path} = \frac{22}{7} \times 1025 \] ### Step 6: Calculate the area - Now, calculate the area: \[ \text{Area of the path} = \frac{22 \times 1025}{7} \] \[ = \frac{22550}{7} \approx 3214.2857 \text{ m}^2 \] - Rounding to one decimal place, we get: \[ \text{Area of the path} \approx 3214.3 \text{ m}^2 \] ### Final Answer The area of the path is approximately **3214.3 m²**. ---
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ICSE-AREA OF A TRAPEZIUM AND A POLYGON-EXERCISE 20(D)
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