Home
Class 10
MATHS
The sum of n natural numbers is 5n^2+4n....

The sum of n natural numbers is `5n^2+4n`. Find the 8th term.

Text Solution

Verified by Experts

The correct Answer is:
79
Promotional Banner

Topper's Solved these Questions

  • ARITHMETIC PROGRESSION

    ICSE|Exercise Exercise 10D|11 Videos

  • ARITHMETIC PROGRESSION

    ICSE|Exercise Exercise 10E|5 Videos

  • ARITHMETIC PROGRESSION

    ICSE|Exercise Exercise 10B|16 Videos

  • BANKING

    ICSE|Exercise Competency Based Questions|10 Videos

Similar Questions

Explore conceptually related problems

Find the sum of first n natural numbers.

Find the sum of first n natural numbers.

Find the sum of first n natural numbers.

For some natural number 'n', the sum of the first 'n' natural numbers is 240 less than the sum of the first (n+5) natural numbers. Then n itself is the sum of how many natural numbers starting with 1.

If the sum of n tems of a series be 5n^2+3n , find its nth term. Are the terms of this series in A.P.?

The sum of n terms of an A.P. is 4n^(2) + 5n. Find the series.

The sum of first n terms of an A.P. is 5n-n^2 . Find the n t h term of this A.P.

Find the sum of first n odd natural numbers.

If the sum of n terms of an A.P. is 2n^2+5n ,\ then its nth term is a. 4n-3 b. 3n-4 c. 4n+3 d. 3n+4

The sum of the first n terms of an A.P. is 3n^2+6n . Find the n^(th) term of this A.P.