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Find what length of canvas, 1.5 m in width, is required to make a conical tent 48 m diameter and 7 m in height ? Given that 10% of the canvas is used in folds and stitchings. Also, find the cost of the canvas at the rate of Rs.24 per metre.

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To solve the problem of finding the length of canvas required to make a conical tent and its cost, we will follow these steps: ### Step 1: Identify the given values - Diameter of the conical tent (D) = 48 m - Height of the conical tent (h) = 7 m - Width of the canvas (b) = 1.5 m - Additional canvas for folds and stitching = 10% ### Step 2: Calculate the radius of the cone The radius (r) is half of the diameter: \[ r = \frac{D}{2} = \frac{48}{2} = 24 \text{ m} \] ### Step 3: Calculate the slant height (l) of the cone Using the Pythagorean theorem: \[ l = \sqrt{r^2 + h^2} = \sqrt{24^2 + 7^2} = \sqrt{576 + 49} = \sqrt{625} = 25 \text{ m} \] ### Step 4: Calculate the curved surface area (CSA) of the cone The formula for the curved surface area of a cone is: \[ \text{CSA} = \pi r l \] Substituting the values: \[ \text{CSA} = \frac{22}{7} \times 24 \times 25 \] Calculating this: \[ \text{CSA} = \frac{22 \times 24 \times 25}{7} = \frac{13200}{7} \text{ m}^2 \] ### Step 5: Calculate the total area of canvas required Since 10% of the canvas is used for folds and stitching, the total area needed is: \[ \text{Total Area} = \text{CSA} \times \frac{110}{100} = \frac{13200}{7} \times 1.1 = \frac{14520}{7} \text{ m}^2 \] ### Step 6: Relate the area of the canvas to its length The area of the rectangular canvas is given by: \[ \text{Area} = \text{Length} \times \text{Width} = L \times 1.5 \] Setting this equal to the total area needed: \[ L \times 1.5 = \frac{14520}{7} \] Solving for L: \[ L = \frac{14520}{7 \times 1.5} = \frac{14520}{10.5} = \frac{14520 \div 10.5}{1} = \frac{1380}{1} = 1380 \text{ m} \] ### Step 7: Calculate the cost of the canvas The cost of the canvas per meter is Rs. 24. Therefore, the total cost is: \[ \text{Total Cost} = L \times \text{Cost per meter} = 1380 \times 24 \] Calculating this: \[ \text{Total Cost} = 33120 \text{ Rs} \] ### Final Answers - Length of canvas required = 1380 m - Cost of the canvas = Rs. 33120 ---
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ICSE-CYLINDER, CONE AND SPHERE -EXERCISE 20 (B)
  1. Find the volume of a cone whose slant height is 17 cm and radius of ba...

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  2. The curved surface area of a cone is 12320 cm^(2). If the radius of it...

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  3. The circumference of the base of a 12 m high conical tent is 66 m. Fin...

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  4. The radius and the height of a right circular cone are in the ratio 5 ...

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  5. Two right circular cones x and y are made. x having three times the ra...

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  6. The diameters of two cones are equal. If their slant heights are in th...

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  7. There are two cones. The curved surface area of one is twice that of t...

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  8. A heap of wheat is in the form of a cone of diameter 16.8 m and height...

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  9. Find what length of canvas, 1.5 m in width, is required to make a coni...

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  10. A solid cone of height 8 cm and base radius 6 cm is melted and recast ...

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  11. The total surface area of a right circular cone of slant height 13 cm ...

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  12. The total surface area of a right circular cone of slant height 13 cm ...

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  13. The area of the base of a conical solid is 38.5 cm^(2) and its volume ...

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  14. A vessel, in the form of an inverted cone, is filled with water to the...

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  15. The volume of a conical tent is 1232 m ^(3) and the area of the base f...

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  16. The volume of a conical tent is 1232 m ^(3) and the area of the base f...

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  17. The volume of a conical tent is 1232 m ^(3) and the area of the base f...

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