A normal die is rolled . Calculate the probability that the number on the uppemost face when it stops rolling will be
5

Answer

To solve the problem of finding the probability that the number on the uppermost face of a rolled die is 5, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Sample Space**:
A normal die has six faces, numbered from 1 to 6. Therefore, the sample space \( S \) can be represented as:
\[ S = \{1, 2, 3, 4, 5, 6\} \]
The total number of outcomes, denoted as \( n(S) \), is 6.

2. **Determine Favorable Outcomes**:
We need to find the probability that the uppermost face shows the number 5. There is only one face with the number 5 on it. Thus, the number of favorable outcomes, denoted as \( n(E) \), is:
\[ n(E) = 1 \]

3. **Calculate the Probability**:
The probability \( P(E) \) of an event is calculated using the formula:
\[ P(E) = \frac{n(E)}{n(S)} \]
Substituting the values we found:
\[ P(E) = \frac{1}{6} \]

4. **Conclusion**:
Therefore, the probability that the number on the uppermost face of the die is 5 is:
\[ P(E) = \frac{1}{6} \]