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Find the equatin to the parabola whose a...

Find the equatin to the parabola whose axis is parallel to the y-xis and which passes through the point `(0,4), (1.9)," and "(-2,6)` and determine its latus rectum.

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To find the equation of the parabola whose axis is parallel to the y-axis and which passes through the points (0, 4), (1, 9), and (-2, 6), we can follow these steps: ### Step 1: Write the general form of the parabola Since the axis is parallel to the y-axis, we can express the equation of the parabola in the form: \[ y = ax^2 + bx + c \] ### Step 2: Substitute the first point (0, 4) Substituting the point (0, 4) into the equation: \[ 4 = a(0)^2 + b(0) + c \] This simplifies to: \[ c = 4 \] ### Step 3: Substitute the second point (1, 9) Now, substitute the point (1, 9): \[ 9 = a(1)^2 + b(1) + c \] Substituting \( c = 4 \): \[ 9 = a + b + 4 \] This simplifies to: \[ a + b = 5 \] (Equation 1) ### Step 4: Substitute the third point (-2, 6) Next, substitute the point (-2, 6): \[ 6 = a(-2)^2 + b(-2) + c \] Substituting \( c = 4 \): \[ 6 = 4a - 2b + 4 \] This simplifies to: \[ 4a - 2b = 2 \] Dividing the entire equation by 2 gives: \[ 2a - b = 1 \] (Equation 2) ### Step 5: Solve the system of equations Now we have two equations: 1. \( a + b = 5 \) 2. \( 2a - b = 1 \) We can add these two equations: \[ (a + b) + (2a - b) = 5 + 1 \] This simplifies to: \[ 3a = 6 \] Thus, we find: \[ a = 2 \] ### Step 6: Substitute back to find b Now substitute \( a = 2 \) back into Equation 1: \[ 2 + b = 5 \] This gives: \[ b = 3 \] ### Step 7: Write the final equation of the parabola Now we have \( a = 2 \), \( b = 3 \), and \( c = 4 \). Therefore, the equation of the parabola is: \[ y = 2x^2 + 3x + 4 \] ### Step 8: Determine the latus rectum The length of the latus rectum of a parabola in the form \( y = ax^2 + bx + c \) is given by: \[ \text{Length of latus rectum} = \frac{1}{|a|} \] Here, \( a = 2 \), so: \[ \text{Length of latus rectum} = \frac{1}{2} \] ### Final Answer The equation of the parabola is: \[ y = 2x^2 + 3x + 4 \] And the length of the latus rectum is: \[ \frac{1}{2} \]
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ICSE-PARABOLA-EXERCISE 23
  1. The focus at (-2,-1) and the latus rectum joins the points (-2,2) and ...

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  2. Find the equation of a parabola whose vertex at (-2,3) and the focus a...

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  3. Find the equation of parabola if it's vertex is at (0,0) and the focu...

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  4. Find the equation of the parabola whose vertex is at (0,0) and the foc...

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  5. The axis parallel to the x-axis, and the parabola passes through (3,3)...

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  6. The axis parallel to the x-axis, and the parabola passes through the p...

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  7. The parabola y^2=4px passes thrugh the point (3,-2). Obtain the length...

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  8. Prove that the equation y^(2)+2ax+2by+c=0 represents a parabola whose ...

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  9. Of the parabola, 4(y-1)^(2)= -7(x-3) find The length of the latus re...

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  10. Of the parabola, 4(y-1)^(2)= -7(x-3) find The coordinates of the foc...

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  11. Find the vertex, focus, and directrix of the following parabolas: y^...

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  12. Find the vertex, focus, and directrix of the following parabolas: x^...

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  13. Find the vertex, focus and directix of the parabola (x-h)^(2)+4a(y-k)=...

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  14. Find the equatin to the parabola whose axis is parallel to the y-xis a...

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  15. Find the coordinates of the point on the parabola y^(2)=8x whose focal...

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  16. If the ordinate of a point on the parabola y^(2)=4ax is twice the latu...

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  17. Find the equation of the parabola whose focus is at the origin, and wh...

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  18. The directrix of a conic section is the straight line 3x-4y+5-0 and th...

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  19. Find the equation to the parabola whose focus is (-2,1) and directrix ...

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  20. The length of the latus rectum of the parabola whose focus is (3,3) an...

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