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The directrix of a conic section is the straight line `3x-4y+5-0` and the focus is `(2,3)`. If the eccontricity e is 1, find the equation to the coin section. Is the coin sction a parabola?

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To find the equation of the conic section given the directrix and focus, we will follow these steps: ### Step 1: Identify the given information - Directrix: \(3x - 4y + 5 = 0\) - Focus: \(F(2, 3)\) - Eccentricity \(e = 1\) ### Step 2: Understand the definition of a parabola A parabola is defined as the locus of points where the distance from a point (focus) is equal to the distance from a line (directrix). ### Step 3: Set up the distance equations Let \(P(x, y)\) be a point on the parabola. The distance from \(P\) to the focus \(F(2, 3)\) is given by: \[ PF = \sqrt{(x - 2)^2 + (y - 3)^2} \] The distance from point \(P\) to the directrix \(3x - 4y + 5 = 0\) can be calculated using the formula for the distance from a point to a line: \[ PM = \frac{|3x - 4y + 5|}{\sqrt{3^2 + (-4)^2}} = \frac{|3x - 4y + 5|}{5} \] ### Step 4: Set the distances equal Since \(e = 1\), we have: \[ PF = PM \] Thus, \[ \sqrt{(x - 2)^2 + (y - 3)^2} = \frac{|3x - 4y + 5|}{5} \] ### Step 5: Square both sides to eliminate the square root Squaring both sides gives: \[ (x - 2)^2 + (y - 3)^2 = \left(\frac{3x - 4y + 5}{5}\right)^2 \] ### Step 6: Expand both sides Expanding the left side: \[ (x - 2)^2 + (y - 3)^2 = (x^2 - 4x + 4) + (y^2 - 6y + 9) = x^2 + y^2 - 4x - 6y + 13 \] Expanding the right side: \[ \left(\frac{3x - 4y + 5}{5}\right)^2 = \frac{(3x - 4y + 5)^2}{25} \] \[ = \frac{(9x^2 - 24xy + 16y^2 + 30x - 40y + 25)}{25} \] ### Step 7: Clear the fraction by multiplying through by 25 Multiplying both sides by 25: \[ 25(x^2 + y^2 - 4x - 6y + 13) = 9x^2 - 24xy + 16y^2 + 30x - 40y + 25 \] ### Step 8: Rearrange the equation Expanding the left side: \[ 25x^2 + 25y^2 - 100x - 150y + 325 = 9x^2 - 24xy + 16y^2 + 30x - 40y + 25 \] Rearranging gives: \[ 25x^2 - 9x^2 + 25y^2 - 16y^2 + 24xy - 100x - 30x - 150y + 40y + 325 - 25 = 0 \] \[ 16x^2 + 9y^2 + 24xy - 130x - 110y + 300 = 0 \] ### Step 9: Final equation of the parabola The equation of the parabola is: \[ 16x^2 + 9y^2 + 24xy - 130x - 110y + 300 = 0 \] ### Step 10: Conclusion Since the eccentricity \(e = 1\), we confirm that this conic section is indeed a parabola. ---
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ICSE-PARABOLA-EXERCISE 23
  1. The focus at (-2,-1) and the latus rectum joins the points (-2,2) and ...

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  2. Find the equation of a parabola whose vertex at (-2,3) and the focus a...

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  3. Find the equation of parabola if it's vertex is at (0,0) and the focu...

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  4. Find the equation of the parabola whose vertex is at (0,0) and the foc...

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  5. The axis parallel to the x-axis, and the parabola passes through (3,3)...

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  6. The axis parallel to the x-axis, and the parabola passes through the p...

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  7. The parabola y^2=4px passes thrugh the point (3,-2). Obtain the length...

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  8. Prove that the equation y^(2)+2ax+2by+c=0 represents a parabola whose ...

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  9. Of the parabola, 4(y-1)^(2)= -7(x-3) find The length of the latus re...

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  10. Of the parabola, 4(y-1)^(2)= -7(x-3) find The coordinates of the foc...

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  11. Find the vertex, focus, and directrix of the following parabolas: y^...

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  12. Find the vertex, focus, and directrix of the following parabolas: x^...

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  13. Find the vertex, focus and directix of the parabola (x-h)^(2)+4a(y-k)=...

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  14. Find the equatin to the parabola whose axis is parallel to the y-xis a...

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  15. Find the coordinates of the point on the parabola y^(2)=8x whose focal...

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  16. If the ordinate of a point on the parabola y^(2)=4ax is twice the latu...

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  17. Find the equation of the parabola whose focus is at the origin, and wh...

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  18. The directrix of a conic section is the straight line 3x-4y+5-0 and th...

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  19. Find the equation to the parabola whose focus is (-2,1) and directrix ...

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  20. The length of the latus rectum of the parabola whose focus is (3,3) an...

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