Find the slope of the normal to the curve `x = a sin^(3)t, y = b cos^(3)t` at point where `t = (pi)/(2)`.

Find the slope of the normal to the curve x = a cos^(3) theta, y = a sin^(3) theta at theta = (pi)/(4) . A) 0 B) -1 C) 1 D) none of these

Find the slope of the normal to the curve y= cos^(2) x at x = (pi)/(4)

Find the equation of tangent to the curve given by x=2 sin^(3)t ,y=2 cos^(3)t at a point where t=(pi)/(2) ?

Find the slope of the normal to the curve x=1-asintheta , y=b\ cos^2theta at theta=pi/2 .

Find the slope of the normal to the curve x=a\ cos^3theta , y=a\ sin^3theta at theta=pi/4 .

The slope of normal to the curve y= sin^(2)x and x= (pi)/(4) is

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

Find the equation of normal to the curve x = at^(2), y=2at at point 't'.

The length of the normal at t on the curve x=a(t+sint), y=a(1-cos t), is

x = "sin" t, y = "cos" 2t