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Multiply the 2.4 xx 3.1 xx1.5...

Multiply the
`2.4 xx 3.1 xx1.5`

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To solve the multiplication of \(2.4 \times 3.1 \times 1.5\), we can follow these steps: ### Step 1: Remove the decimals and multiply the numbers as whole numbers. We will first multiply \(24\) (which is \(2.4\) multiplied by \(10\)) by \(15\) (which is \(1.5\) multiplied by \(10\)). \[ 24 \times 15 \] ### Step 2: Perform the multiplication. To multiply \(24\) by \(15\): - Multiply \(24\) by \(5\): \[ 24 \times 5 = 120 \] - Multiply \(24\) by \(10\): \[ 24 \times 10 = 240 \] - Now add these two results: \[ 120 + 240 = 360 \] ### Step 3: Determine the position of the decimal point. In the original numbers, \(2.4\) has 1 decimal place, \(3.1\) has 1 decimal place, and \(1.5\) has 1 decimal place. This gives us a total of \(3\) decimal places. So, we place the decimal point in \(360\) to get \(3.60\) (or simply \(3.6\)). ### Step 4: Now multiply the result \(3.6\) by \(3.1\). Again, we will ignore the decimal and multiply \(36\) by \(31\). \[ 36 \times 31 \] ### Step 5: Perform the multiplication. To multiply \(36\) by \(31\): - Multiply \(36\) by \(1\): \[ 36 \times 1 = 36 \] - Multiply \(36\) by \(30\): \[ 36 \times 30 = 1080 \] - Now add these two results: \[ 36 + 1080 = 1116 \] ### Step 6: Determine the position of the decimal point again. In \(3.6\) there is 1 decimal place and in \(3.1\) there is also 1 decimal place, giving us a total of \(2\) decimal places. So, we place the decimal point in \(1116\) to get \(11.16\). ### Final Answer: \[ 2.4 \times 3.1 \times 1.5 = 11.16 \] ---
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