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One - fourth of a herd of deer have gone...

One - fourth of a herd of deer have gone to the forest. One - third of the total number of deer are grazing in a field and the remaining 15 are drinking water on the bank of a river . Find the total number of deer in the herd.

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To solve the problem step by step, let's denote the total number of deer in the herd as \( x \). ### Step 1: Define the variables Let the total number of deer in the herd be \( x \). ### Step 2: Express the number of deer in different locations - One-fourth of the herd has gone to the forest: \[ \text{Deer in the forest} = \frac{x}{4} \] - One-third of the total number of deer are grazing in a field: \[ \text{Deer in the field} = \frac{x}{3} \] - The remaining deer are drinking water on the bank of a river, which is given as 15: \[ \text{Deer drinking water} = 15 \] ### Step 3: Set up the equation The total number of deer can be expressed as the sum of deer in the forest, deer in the field, and deer drinking water: \[ \frac{x}{4} + \frac{x}{3} + 15 = x \] ### Step 4: Find a common denominator To solve the equation, we need to find a common denominator for the fractions. The least common multiple of 4 and 3 is 12. We will rewrite the equation: \[ \frac{3x}{12} + \frac{4x}{12} + 15 = x \] ### Step 5: Combine the fractions Now combine the fractions on the left side: \[ \frac{3x + 4x}{12} + 15 = x \] This simplifies to: \[ \frac{7x}{12} + 15 = x \] ### Step 6: Isolate \( x \) To isolate \( x \), we will subtract \( \frac{7x}{12} \) from both sides: \[ 15 = x - \frac{7x}{12} \] This can be rewritten as: \[ 15 = \frac{12x - 7x}{12} \] Which simplifies to: \[ 15 = \frac{5x}{12} \] ### Step 7: Solve for \( x \) To solve for \( x \), multiply both sides by 12: \[ 15 \times 12 = 5x \] \[ 180 = 5x \] Now divide both sides by 5: \[ x = \frac{180}{5} = 36 \] ### Conclusion The total number of deer in the herd is \( \boxed{36} \). ---
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