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Solve: 2(3x-2)-3(4-5x)=7(1-2x)+12...

Solve: `2(3x-2)-3(4-5x)=7(1-2x)+12`

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To solve the equation \( 2(3x - 2) - 3(4 - 5x) = 7(1 - 2x) + 12 \), we will follow these steps: ### Step 1: Expand the brackets First, we will expand both sides of the equation. \[ 2(3x - 2) = 6x - 4 \] \[ -3(4 - 5x) = -12 + 15x \] \[ 7(1 - 2x) = 7 - 14x \] Substituting these into the equation gives us: \[ 6x - 4 - 12 + 15x = 7 - 14x + 12 \] ### Step 2: Combine like terms Now, we combine like terms on both sides. Left side: \[ 6x + 15x - 4 - 12 = 21x - 16 \] Right side: \[ 7 + 12 - 14x = 19 - 14x \] So, the equation now looks like this: \[ 21x - 16 = 19 - 14x \] ### Step 3: Move all terms involving \( x \) to one side Next, we will move \( -14x \) to the left side and \( -16 \) to the right side. Adding \( 14x \) to both sides: \[ 21x + 14x = 19 + 16 \] ### Step 4: Simplify both sides Now we simplify both sides: Left side: \[ 35x \] Right side: \[ 19 + 16 = 35 \] So we have: \[ 35x = 35 \] ### Step 5: Solve for \( x \) Finally, we divide both sides by 35 to isolate \( x \): \[ x = \frac{35}{35} = 1 \] ### Final Answer Thus, the solution to the equation is: \[ x = 1 \] ---
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