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Solve the following equations and verify...

Solve the following equations and verify the results.
`2/5(4-2x)-3/4(2-5x)=7/5`

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To solve the equation \( \frac{2}{5}(4 - 2x) - \frac{3}{4}(2 - 5x) = \frac{7}{5} \), we will follow these steps: ### Step 1: Distribute the fractions Distributing the fractions on the left-hand side: \[ \frac{2}{5} \cdot 4 - \frac{2}{5} \cdot 2x - \frac{3}{4} \cdot 2 + \frac{3}{4} \cdot 5x \] Calculating each term: \[ \frac{8}{5} - \frac{4}{5}x - \frac{6}{4} + \frac{15}{4}x \] Now, simplify \(\frac{6}{4}\) to \(\frac{3}{2}\): \[ \frac{8}{5} - \frac{4}{5}x - \frac{3}{2} + \frac{15}{4}x \] ### Step 2: Find a common denominator The common denominator for \(5\) and \(4\) is \(20\). We will convert each term to have a denominator of \(20\): \[ \frac{8 \cdot 4}{20} - \frac{4 \cdot 4}{20}x - \frac{3 \cdot 10}{20} + \frac{15 \cdot 5}{20}x \] This simplifies to: \[ \frac{32}{20} - \frac{16}{20}x - \frac{30}{20} + \frac{75}{20}x \] ### Step 3: Combine like terms Combine the constant terms and the \(x\) terms: \[ \left(\frac{32}{20} - \frac{30}{20}\right) + \left(-\frac{16}{20}x + \frac{75}{20}x\right) \] This simplifies to: \[ \frac{2}{20} + \frac{59}{20}x = \frac{7}{5} \] ### Step 4: Clear the fractions Multiply the entire equation by \(20\) to eliminate the denominators: \[ 2 + 59x = 28 \] ### Step 5: Solve for \(x\) Subtract \(2\) from both sides: \[ 59x = 26 \] Now, divide by \(59\): \[ x = \frac{26}{59} \] ### Step 6: Verification Substituting \(x = \frac{26}{59}\) back into the original equation: \[ \frac{2}{5}\left(4 - 2\left(\frac{26}{59}\right)\right) - \frac{3}{4}\left(2 - 5\left(\frac{26}{59}\right)\right) \] Calculating \(4 - 2\left(\frac{26}{59}\right)\): \[ 4 - \frac{52}{59} = \frac{236}{59} - \frac{52}{59} = \frac{184}{59} \] Now calculate: \[ \frac{2}{5} \cdot \frac{184}{59} = \frac{368}{295} \] Now for \(2 - 5\left(\frac{26}{59}\right)\): \[ 2 - \frac{130}{59} = \frac{118}{59} - \frac{130}{59} = -\frac{12}{59} \] Calculating: \[ -\frac{3}{4} \cdot -\frac{12}{59} = \frac{36}{236} = \frac{9}{59} \] Now combine both parts: \[ \frac{368}{295} + \frac{9}{59} \] Finding a common denominator for \(295\) and \(59\) (which is \(295\)): \[ \frac{368}{295} + \frac{45}{295} = \frac{413}{295} \] Now simplify \(\frac{413}{295}\) to see if it equals \(\frac{7}{5}\): \[ \frac{413}{295} = \frac{7 \cdot 59}{5 \cdot 59} = \frac{413}{295} \] Thus, the left-hand side equals the right-hand side. ### Final Answer The solution to the equation is: \[ x = \frac{26}{59} \]
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ICSE-SIMPLE LINEAR EQUATIONS -Revision Exercise
  1. Solve the following equations and verify the results. 2/9(x+3)=4x-7

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  2. Solve the following equations and verify the results. 4(3x+5)-6(2-x)...

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  3. Solve the following equations and verify the results. 2/5(4-2x)-3/4(...

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  4. In a class, the number of boys is 3/2 times the number of girls. If th...

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  5. Find four consecutive odd numbers whose sum is 136.

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  6. A number is such that it is as much greater than 84 as it is less than...

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  7. Eight more than 5 times a number is 78. Find the number.

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  8. Seven eighths of a number is greater than half the number by 9. Find t...

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  9. A number consists of two digits that add up to 7. If 27 is added to th...

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  10. A number is doubled to get a second number which is further doubled to...

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  11. A two-digit number is such that the sum of its two digits is 11. If 27...

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  12. Suresh has three boxes of different fruits. Box 1 weighs 2(1)/2 -kg mo...

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  13. Rahul's age is one-fourth of Seema's age. If the difference between th...

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  14. Sudha is four times as old as Rita. After 12 years, Sudha will be twic...

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  15. Alka's age is 5 years more than 4 times the age of Suman. If Alka's ag...

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  16. The length of a rectangular field is twice its breadth. If the perimet...

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  17. A silk scarf is in the shape of an isosceles triangle. The two equal s...

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  18. Two complimentary angles differ by 44^@ Find the two angles

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  19. The difference between two supplementary angles is 72^@ Find the angl...

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  20. A man spends one-third of his monthly income on food, one-fourth on ch...

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