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In an examination, a student requires 40...

In an examination, a student requires 40% of the total marks to pass. If the student secures 185 marks and fails by 15 marks, find the total marks.

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To solve the problem step by step, we can follow this approach: ### Step 1: Understand the problem The student needs 40% of the total marks to pass the examination. The student scored 185 marks but failed by 15 marks. ### Step 2: Calculate the passing marks Since the student failed by 15 marks, we can find the passing marks by adding the marks the student scored to the marks he failed by. \[ \text{Passing Marks} = \text{Marks Secured} + \text{Marks Failed By} \] \[ \text{Passing Marks} = 185 + 15 = 200 \] ### Step 3: Set up the equation for total marks We know that the passing marks (200) is equal to 40% of the total marks (let's denote total marks as \( T \)). We can write this as an equation: \[ 200 = 40\% \text{ of } T \] \[ 200 = \frac{40}{100} \times T \] ### Step 4: Solve for total marks To find \( T \), we can rearrange the equation: \[ 200 = \frac{40}{100} \times T \] \[ 200 = \frac{2}{5} \times T \] Now, to isolate \( T \), we can multiply both sides by \( \frac{5}{2} \): \[ T = 200 \times \frac{5}{2} \] \[ T = 200 \times 2.5 \] \[ T = 500 \] ### Conclusion The total marks for the examination is \( 500 \). ---
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