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Find the simple interest on : a. ₹3500...

Find the simple interest on :
a. `₹3500` at `4%` p.a. for `5` years.
b. `₹4300` at `6%` p.a. for `3` years.

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The correct Answer is:
To find the simple interest for the given amounts, we will use the formula for simple interest: \[ \text{Simple Interest (SI)} = \frac{P \times R \times T}{100} \] where: - \( P \) = Principal amount (the initial amount of money) - \( R \) = Rate of interest per annum (in percentage) - \( T \) = Time (in years) ### Part a: Find the simple interest on ₹3500 at 4% p.a. for 5 years. 1. **Identify the values**: - Principal (P) = ₹3500 - Rate (R) = 4% - Time (T) = 5 years 2. **Substitute the values into the formula**: \[ SI = \frac{3500 \times 4 \times 5}{100} \] 3. **Calculate the multiplication**: - First, calculate \( 3500 \times 4 = 14000 \) - Then, calculate \( 14000 \times 5 = 70000 \) 4. **Divide by 100**: \[ SI = \frac{70000}{100} = 700 \] So, the simple interest for part a is **₹700**. ### Part b: Find the simple interest on ₹4300 at 6% p.a. for 3 years. 1. **Identify the values**: - Principal (P) = ₹4300 - Rate (R) = 6% - Time (T) = 3 years 2. **Substitute the values into the formula**: \[ SI = \frac{4300 \times 6 \times 3}{100} \] 3. **Calculate the multiplication**: - First, calculate \( 4300 \times 6 = 25800 \) - Then, calculate \( 25800 \times 3 = 77400 \) 4. **Divide by 100**: \[ SI = \frac{77400}{100} = 774 \] So, the simple interest for part b is **₹774**. ### Summary of Results: - Part a: Simple Interest = **₹700** - Part b: Simple Interest = **₹774** ---
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