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Let A and B be two sets such that n (A) ...

Let A and B be two sets such that `n (A) = 52, n (B) = 60 and n(A nn B) = 16. ` Draw a Venn diagram and find
`n(A uuB ) `

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To solve the problem, we need to find the number of elements in the union of sets A and B, denoted as \( n(A \cup B) \). We are given the following information: - \( n(A) = 52 \) - \( n(B) = 60 \) - \( n(A \cap B) = 16 \) ### Step 1: Use the formula for the union of two sets The formula for the number of elements in the union of two sets is given by: \[ n(A \cup B) = n(A) + n(B) - n(A \cap B) \] ### Step 2: Substitute the given values into the formula Now, we substitute the values we have into the formula: \[ n(A \cup B) = n(A) + n(B) - n(A \cap B) \] \[ n(A \cup B) = 52 + 60 - 16 \] ### Step 3: Perform the arithmetic Now we perform the addition and subtraction: \[ n(A \cup B) = 112 - 16 \] \[ n(A \cup B) = 96 \] ### Conclusion Thus, the number of elements in the union of sets A and B is: \[ n(A \cup B) = 96 \] ### Venn Diagram To draw the Venn diagram: 1. Draw a rectangle to represent the universal set \( U \). 2. Draw two overlapping circles inside the rectangle. Label one circle as set \( A \) and the other as set \( B \). 3. In the overlapping area (the intersection), write the number of elements in \( A \cap B \), which is 16. 4. In the part of circle \( A \) that does not overlap with circle \( B \), write \( n(A) - n(A \cap B) = 52 - 16 = 36 \). 5. In the part of circle \( B \) that does not overlap with circle \( A \), write \( n(B) - n(A \cap B) = 60 - 16 = 44 \).
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ICSE-SETS -EXERCISE 6 D
  1. Let A and B be two sets such that n (A) = 52, n (B) = 60 and n(A nn B...

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  2. Let A and B be two sets such that n (A) = 52, n (B) = 60 and n(A nn B...

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  3. Let A and B be two sets such that n (A) = 52, n (B) = 60 and n(A nn B...

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  4. Let P and Q be two sets such that n(P uu Q) = 70 ,n (P )= 45 and n(Q)...

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  5. Let P and Q be two sets such that n(P uu Q) = 70 ,n (P )= 45 and n(Q)...

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  6. Let P and Q be two sets such that n(P uu Q) = 70 ,n (P )= 45 and n(Q)...

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