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Find the rate of interest if : a. the ...

Find the rate of interest if :
a. the interest on `₹1800` for `4` years is `₹432`.
b. the interest on `₹2200` for `3` years is `₹330`.

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The correct Answer is:
To find the rate of interest for the given scenarios, we will use the formula for Simple Interest (SI): \[ SI = \frac{P \times R \times T}{100} \] Where: - \( SI \) = Simple Interest - \( P \) = Principal amount - \( R \) = Rate of interest (in percentage) - \( T \) = Time (in years) ### Part (a) **Step 1: Identify the values.** - Principal (P) = ₹1800 - Time (T) = 4 years - Simple Interest (SI) = ₹432 **Step 2: Substitute the values into the formula.** \[ 432 = \frac{1800 \times R \times 4}{100} \] **Step 3: Simplify the equation.** Multiply both sides by 100: \[ 43200 = 1800 \times R \times 4 \] **Step 4: Calculate \( 1800 \times 4 \).** \[ 1800 \times 4 = 7200 \] So, the equation becomes: \[ 43200 = 7200 \times R \] **Step 5: Solve for R.** Divide both sides by 7200: \[ R = \frac{43200}{7200} \] \[ R = 6 \] **Step 6: Conclusion for Part (a).** The rate of interest is **6%**. --- ### Part (b) **Step 1: Identify the values.** - Principal (P) = ₹2200 - Time (T) = 3 years - Simple Interest (SI) = ₹330 **Step 2: Substitute the values into the formula.** \[ 330 = \frac{2200 \times R \times 3}{100} \] **Step 3: Simplify the equation.** Multiply both sides by 100: \[ 33000 = 2200 \times R \times 3 \] **Step 4: Calculate \( 2200 \times 3 \).** \[ 2200 \times 3 = 6600 \] So, the equation becomes: \[ 33000 = 6600 \times R \] **Step 5: Solve for R.** Divide both sides by 6600: \[ R = \frac{33000}{6600} \] \[ R = 5 \] **Step 6: Conclusion for Part (b).** The rate of interest is **5%**. ---
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