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One exterior angle of a triangle is 70^(...

One exterior angle of a triangle is `70^(@)`. The two opposite interior angles are in the ratio 2:5. find the angles of the triangle.

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To find the angles of the triangle given that one exterior angle is \(70^\circ\) and the two opposite interior angles are in the ratio \(2:5\), we can follow these steps: ### Step 1: Understand the relationship between the exterior angle and the interior angles The exterior angle of a triangle is equal to the sum of the two opposite interior angles. In this case, we have: \[ \text{Exterior angle} = 70^\circ \] Let the two opposite interior angles be \(A\) and \(B\). According to the exterior angle property: \[ A + B = 70^\circ \] ### Step 2: Express the interior angles in terms of a variable Given that the two angles are in the ratio \(2:5\), we can express them as: \[ A = 2x \quad \text{and} \quad B = 5x \] ### Step 3: Substitute the expressions into the equation Now we can substitute \(A\) and \(B\) into the equation from Step 1: \[ 2x + 5x = 70^\circ \] ### Step 4: Combine like terms Combine the terms on the left side: \[ 7x = 70^\circ \] ### Step 5: Solve for \(x\) Now, divide both sides by \(7\): \[ x = \frac{70^\circ}{7} = 10^\circ \] ### Step 6: Find the values of angles \(A\) and \(B\) Now that we have \(x\), we can find the angles \(A\) and \(B\): \[ A = 2x = 2 \times 10^\circ = 20^\circ \] \[ B = 5x = 5 \times 10^\circ = 50^\circ \] ### Step 7: Find the third angle of the triangle The third angle \(C\) can be calculated using the fact that the sum of the angles in a triangle is \(180^\circ\): \[ C = 180^\circ - (A + B) = 180^\circ - (20^\circ + 50^\circ) = 180^\circ - 70^\circ = 110^\circ \] ### Final Angles of the Triangle Thus, the angles of the triangle are: \[ A = 20^\circ, \quad B = 50^\circ, \quad C = 110^\circ \] ### Summary of Angles The angles of the triangle are \(20^\circ\), \(50^\circ\), and \(110^\circ\). ---
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ICSE-THE TRIANGLE AND ITS PROPERTIES-TRY THIS
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