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If NaCl is doped with 10^(-3) mol % SrCl...

If NaCl is doped with `10^(-3) mol % SrCl_2`, what is the concentration of cation vacancies?

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To find the concentration of cation vacancies when NaCl is doped with \(10^{-3}\) mol % SrCl\(_2\), we can follow these steps: ### Step 1: Understand the Doping Process When NaCl is doped with SrCl\(_2\), the strontium ions (Sr\(^{2+}\)) replace sodium ions (Na\(^{+}\)). Since Sr\(^{2+}\) has a +2 charge, it creates a cation vacancy in the NaCl lattice to maintain charge neutrality. ### Step 2: Convert Mole Percentage to Moles Given: - Doping concentration = \(10^{-3}\) mol % ...
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