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Show that the modulus function f: R->...

Show that the modulus function `f: R->R` , given by `f(x)=|x|` is neither one-one nor onto.

A

One-one but not onto

B

Onto but not one-one

C

Bijective

D

Neither one-one nor onto

Text Solution

Verified by Experts

The correct Answer is:
D
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