Home
Class 12
MATHS
Find the break even points when, p= 72-4...

Find the break even points when, `p= 72-4x, C(x) = 16x + 180`

Text Solution

AI Generated Solution

The correct Answer is:
To find the break-even points where total revenue equals total cost, we will follow these steps: ### Step 1: Define the Revenue and Cost Functions The price function is given as: \[ P = 72 - 4x \] The cost function is given as: \[ C(x) = 16x + 180 \] ### Step 2: Write the Total Revenue Function Total revenue (R) is calculated as the product of price (P) and quantity (x): \[ R(x) = P \cdot x = (72 - 4x) \cdot x \] Expanding this: \[ R(x) = 72x - 4x^2 \] ### Step 3: Set Revenue Equal to Cost To find the break-even points, we set the total revenue equal to the total cost: \[ R(x) = C(x) \] Thus, \[ 72x - 4x^2 = 16x + 180 \] ### Step 4: Rearrange the Equation Rearranging the equation gives us: \[ 72x - 4x^2 - 16x - 180 = 0 \] Combining like terms: \[ -4x^2 + 56x - 180 = 0 \] Multiplying through by -1 to simplify: \[ 4x^2 - 56x + 180 = 0 \] ### Step 5: Simplify the Quadratic Equation Dividing the entire equation by 4: \[ x^2 - 14x + 45 = 0 \] ### Step 6: Factor the Quadratic Equation We can factor the quadratic: \[ x^2 - 9x - 5x + 45 = 0 \] Grouping the terms: \[ (x - 9)(x - 5) = 0 \] ### Step 7: Solve for x Setting each factor to zero gives us: 1. \( x - 9 = 0 \) → \( x = 9 \) 2. \( x - 5 = 0 \) → \( x = 5 \) ### Conclusion The break-even points are: \[ x = 5 \text{ and } x = 9 \]
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER-5

    ICSE|Exercise Section-B|10 Videos
  • MODEL TEST PAPER-16

    ICSE|Exercise SECTION -C (65 MARKS)|10 Videos
  • MODEL TEST PAPER-6

    ICSE|Exercise Section -C|10 Videos

Similar Questions

Explore conceptually related problems

Find the remainder when p(x)=4x^3-12 x^2+14 x-3 is divided by g(x)=x-1/2

Find the remainder when p(x)=4x^3-12 x^2+14 x-3 is divided by g(x)=x-1/2

BY Remainder theorem , find the remainder when p(x) is divided by g(x) (i) p(x) =x^(3)-2x^(2)-4x-1, g(x)=x+1 (ii) p(x) =x^(3)-3x^(2)+4x+50, g(x) =x-3

Using integration, find the area of the region bounded by the parabola y^2=16x and the line x=4

Find the tangent to the y ^(2) = 16x, making of 45 ^(@) with the x-axis.

Find the area bounded by y=-x^(3)+x^(2)+16x and y=4x

Let p(x)=x^4-3x^2+2x+5. Find the remainder when p(x) is divided by (x-1)dot

Find the remainder when the polynomial p(x)=x^(4)-3x^(2)+5x+1 is divided by (x-2).

Find the value of 64 x^3-\ 125 z^3, if 4x-5z=16 and x z=12

The equation of the normal at the point P (2, 3) on the ellipse 9x^(2) + 16y^(2) = 180 , is