In the given figure, AC = AE, AB = AD and `angle BAD = angle EAC`. Show that : BC = DE.

In the given figure, AC=AE, AB=AD and angleBAD=angleEAC . Prove that BC=DE .

In the following figure AB = AD , AC = AE and angle BAD = angle CAE, Prove that :BC = ED

In the following figure, AB = EF, BC = DE and angle B = angle E = 90^(@) . Pove that AD = FC.

In the given figure, AD = DB = DE angle EAC = angle FAC and angle F = 90 ^(@) Prove that (i) angle AEB = 90 ^(@) (ii) Delta CEG is isosceles. (iii) angle CEG = angle EAF

ABCDE is a pentagon in which AB = AE, BC = ED and angle ABC = angle AED. Prove that AC= AD (ii) angle BCD= angle EDC

In the figure if AB || CD and AD||BC, find angleA and angleD

In the given figure,if AB= AC, angle BAD=30^(@)and AE=AD, then x is equal to

In the given figure, AB = AC. Prove that AF is greater than AE.

In the following diagram, AD = AB and AE bisects angle A. Prove that : (i) BE = DE (ii) angleABD gt angleC

In the given figures, AB > AC and D is any point on BC. Prove that : AB >AD.