`f:xto` highest prime factor of x.
State a domain of five integers for which the range is (3).

Answer

To solve the problem, we need to find a domain of five integers such that the highest prime factor of each integer in the domain is 3. This means that we are looking for integers whose prime factors do not exceed 3, with 3 being the highest.

### Step-by-Step Solution:

1. **Understanding the Function**: The function \( f(x) \) is defined as the highest prime factor of \( x \). We need to find integers \( x \) such that \( f(x) = 3 \).

2. **Identifying Candidates**: We need to find integers whose highest prime factor is 3. This means that the integers can only be composed of the prime factors 2 and 3.

3. **Finding Suitable Integers**:
- **3**: The integer 3 itself has the highest prime factor of 3.
- **6**: The integer 6 has prime factors 2 and 3, with the highest being 3.
- **9**: The integer 9 has prime factors 3 and 3 (i.e., \( 3^2 \)), so the highest is also 3.
- **12**: The integer 12 has prime factors 2, 2, and 3, with the highest being 3.
- **18**: The integer 18 has prime factors 2 and 3, with the highest being 3.

4. **Finalizing the Domain**: We can select the following five integers as our domain:
- \( \{3, 6, 9, 12, 18\} \)

5. **Verifying the Range**: For each integer in the domain, we check that the highest prime factor is indeed 3:
- \( f(3) = 3 \)
- \( f(6) = 3 \)
- \( f(9) = 3 \)
- \( f(12) = 3 \)
- \( f(18) = 3 \)

Thus, the range of the function \( f \) for the given domain is \( \{3\} \).

### Final Answer:
The domain of five integers for which the range is \( \{3\} \) is:
\[ \{3, 6, 9, 12, 18\} \]