Find the value of G from the following data. Mass of the earth `= 6 xx 10^(24) kg`, radius of the earth = 6371km and `g = 9.8 m//s`
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AI Generated Solution
To find the value of the universal gravitational constant \( G \) using the given data, we can use the formula for acceleration due to gravity \( g \):
\[
g = \frac{G \cdot M}{R^2}
\]
Where:
- \( g \) is the acceleration due to gravity (9.8 m/s²),
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Find the ratio of escape velocities from the earth and the moon. (Mass of the earth = 6.0 xx 10^(24) kg , Radius of the earth = 6400 km, Mass of the moon = 7.4 xx 10^(22) kg Radius of the moon = 1740 km.)
A rocket is fired vertically with a speed of 5 km s^(-1) from the earth's surface. How far from the earth does the rocket go before returning to the erath? Mass of the earth = 6.0 xx 10^(24) kg , mean radius of the earth = 6.4 xx 10^(6) m. G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .
Assuming the earth b to be a homogeneous sphere determine the density of the earth from the following data. g = 9.8 m//s^(2), G = 6.67 xx 10^(-11) Nm^(2) kg^(2) , radius of the earth = 6372km.
If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?
Calculate the mass of the earth from the following data. Radius of the earth, 6371km, g = 9.8 ms^(-2)
Find the ratio of the orbital speeds to two satellites one of which is rotating round the earth and the other around Mars close to their surface. (mass of the earth = 6 xx 10^(24) kg , Mass of the Mars = 6.4 xx 10^(23)kg , Radius of the earth = 6400 km and radius of Mars = 3400 km)
A rocket is fired vertically with a speed of 5 kms^(-1) from the earth's surface. How far from the earth does the rocket go before returning to the earth ? Mass of earth= 6.0xx10^(24) kg, mean radius of the earth = 6.4xx10^(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2).
A satellite orbits the earth at a height of 400 km, above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence ? Mass of the satellite=200 kg, mass of the earth= 6.0xx10^(24) kg, radius of the earth= 6.4xx10(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2) .
A satellite orbits the earth at a height of 400 km, above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence ? Mass of the satellite=200 kg, mass of the earth= 6.0xx10^(24) kg, radius of the earth= 6.4xx10(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2) .
What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .
