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The time period of a simple pendulum of length 9.8 m is

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The time period of a simple pendulum of length L as measured in an elevator descending with acceleration g / 3 is

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Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

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ICSE-GRAVITATION-SHORT ANSWER QUESTIONS
  1. Write a note on synchronous satellite.

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  2. Derive an expression for the period of a geostationary satellite.

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  3. Write a note on apiculture.

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  4. Derive an expression for the escape velocity of a body from any planet...

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  5. Can you find the mass of sun without weighing?

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  6. Explain why some planets do not have atmosphere.

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  7. What are the conditions for a satellite to be stationary?

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  8. (a) Explain Stokes Law (b) Define terminal velocity (c) Describe a...

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  9. What is the energy of a satellite revolving in a stable orbit.

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  10. Suppose a body is carried from earth to moon. What happens to its weig...

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  11. If the diameter of the earth becomes two times its present value and i...

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  12. "No fuel is required for satellite to revolve round earth. But fuel re...

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  13. A satellite is launched into a circular orbit of radius R around earth...

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  14. What is a parking orbit ? Why is it called so ?

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  15. A ball is released from height h and another from 2h. The ratio of tim...

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  16. The time period of a simple pendulum of length 9.8 m is

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  17. Assertion : The principle of superposition is not valid for gravitatio...

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  18. What is the frequency of oscillation of a simple pendulum mounted in a...

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  19. To an astronaut in a space-ship, the earth appears :

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  20. Which of the following reactions isnot correct according to the law of...

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