A 50kg boy is standing near a 60 kg girl. If the distance between them is 1m, calculate the gravitational force of attraction between them?

Explanation

To calculate the gravitational force of attraction between a 50 kg boy and a 60 kg girl standing 1 meter apart, we can use the formula for gravitational force:

\[ F = \frac{G \cdot M_1 \cdot M_2}{R^2} \]

Where:
- \( F \) is the gravitational force of attraction,
- \( G \) is the universal gravitational constant, approximately \( 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \),
- \( M_1 \) is the mass of the first object (the boy), which is 50 kg,
- \( M_2 \) is the mass of the second object (the girl), which is 60 kg,
- \( R \) is the distance between the two objects, which is 1 m.

### Step-by-Step Solution:

1. **Identify the values:**
- Mass of the boy, \( M_1 = 50 \, \text{kg} \)
- Mass of the girl, \( M_2 = 60 \, \text{kg} \)
- Distance between them, \( R = 1 \, \text{m} \)
- Gravitational constant, \( G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \)

2. **Substitute the values into the formula:**
\[ F = \frac{(6.67 \times 10^{-11}) \cdot (50) \cdot (60)}{(1)^2} \]

3. **Calculate the numerator:**
- First, calculate \( 50 \cdot 60 = 3000 \).
- Then, multiply by \( G \):
\[ 6.67 \times 10^{-11} \cdot 3000 = 2.001 \times 10^{-7} \, \text{N m}^2/\text{kg}^2 \]

4. **Calculate the denominator:**
- Since \( R^2 = 1^2 = 1 \), the denominator is simply 1.

5. **Final calculation:**
\[ F = \frac{2.001 \times 10^{-7}}{1} = 2.001 \times 10^{-7} \, \text{N} \]

6. **Round the answer:**
- The gravitational force of attraction can be approximated as \( 2 \times 10^{-7} \, \text{N} \).

### Final Answer:
The gravitational force of attraction between the boy and the girl is approximately \( 2 \times 10^{-7} \, \text{N} \).