Home
Class 11
PHYSICS
Compare the weigths of a body when it is...

Compare the weigths of a body when it is kept (i) 400m above the surface of the earth and (ii) 800 m below the surface of the earth.

Text Solution

AI Generated Solution

The correct Answer is:
To compare the weights of a body when it is (i) 400 m above the surface of the Earth and (ii) 800 m below the surface of the Earth, we will use the formulas for gravitational acceleration at different heights and depths. ### Step-by-Step Solution: 1. **Understand the Problem:** We need to find the weight of a body at two different positions: 400 m above the Earth's surface and 800 m below the Earth's surface. The weight of a body is given by the formula: \[ W = m \cdot g \] where \( W \) is the weight, \( m \) is the mass of the body, and \( g \) is the acceleration due to gravity. 2. **Weight Above the Surface:** For a height \( h \) above the Earth's surface, the formula for \( g \) is: \[ g_h = g \left(1 - \frac{2h}{R}\right) \] where \( g \) is the acceleration due to gravity at the surface of the Earth and \( R \) is the radius of the Earth. For \( h = 400 \) m: \[ g_{400} = g \left(1 - \frac{2 \times 400}{R}\right) \] 3. **Weight Below the Surface:** For a depth \( d \) below the Earth's surface, the formula for \( g \) is: \[ g_d = g \left(1 - \frac{d}{R}\right) \] For \( d = 800 \) m: \[ g_{800} = g \left(1 - \frac{800}{R}\right) \] 4. **Calculate the Weights:** Now we can express the weights at both positions: - Weight at 400 m above the surface: \[ W_{above} = m \cdot g_{400} = m \cdot g \left(1 - \frac{2 \times 400}{R}\right) \] - Weight at 800 m below the surface: \[ W_{below} = m \cdot g_{800} = m \cdot g \left(1 - \frac{800}{R}\right) \] 5. **Compare the Weights:** To compare the weights, we can take the ratio: \[ \frac{W_{above}}{W_{below}} = \frac{g \left(1 - \frac{2 \times 400}{R}\right)}{g \left(1 - \frac{800}{R}\right)} = \frac{1 - \frac{800}{R}}{1 - \frac{800}{R}} \] Since \( g \) cancels out, we can simplify this to: \[ W_{above} = W_{below} \] 6. **Conclusion:** Therefore, the weight of the body at 400 m above the surface of the Earth is equal to the weight of the body at 800 m below the surface of the Earth. ### Final Answer: The weight of the body at 400 m above the Earth's surface is equal to the weight of the body at 800 m below the Earth's surface.

To compare the weights of a body when it is (i) 400 m above the surface of the Earth and (ii) 800 m below the surface of the Earth, we will use the formulas for gravitational acceleration at different heights and depths. ### Step-by-Step Solution: 1. **Understand the Problem:** We need to find the weight of a body at two different positions: 400 m above the Earth's surface and 800 m below the Earth's surface. The weight of a body is given by the formula: \[ W = m \cdot g ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    ICSE|Exercise SELECTED PROBLEMS[FROM INTENSITY OF GRAVITATIONAL FIELD AND GRAVITATIONAL POTENTIAL]|7 Videos
  • GRAVITATION

    ICSE|Exercise SELECTED PROBLEMS[FROM GRAVITATIONAL POTENTIAL ENERGY]|4 Videos
  • GRAVITATION

    ICSE|Exercise SELECTED PROBLEMS[FROM MASS , DENSITY OF EARTH, PLANETS]|9 Videos
  • FRICTION

    ICSE|Exercise Selected problems|30 Videos
  • INTERNAL ENERGY

    ICSE|Exercise SELECTED PROBLEMS (FROM HEAT ENGINES)|21 Videos

Similar Questions

Explore conceptually related problems

What is the ratio of the weights of a body when it is kept at a height 500m above the surface of the earth and 500m below the surface of the earth, if the radius of the earth is 6400km.

A body weight 500 N on the surface of the earth. How much would it weigh half way below the surface of the earth

Find the percentage decrease in the weight of a body when taken 16 km below the surface of the earth. Take radius of the earth is 6400 km.

The change in the gravitational potential energy when a body of a mass m is raised to a height nR above the surface of the earth is (here R is the radius of the earth)

Find the change in the gravitational potential energy when a body of mass m is raised to a height nR above the surface of the earth. (Here, R is the radius of the earth)

Determine the decrease in the weight of a body when it is taken 32 km below the earth surface. Take radius of the earth as 6400 km.

If the value of g at the surface of the earth is 9.8 m//sec^(2) , then the value of g at a place 480 km above the surface of the earth will be (Radius of the earth is 6400 km)

At what altitude, the acceleration due to gravity reduces to half of its value as that on the surface of the earth ? Take radius of earth as 6.410^(6) m, g on the surface of the earth as 9.8 m//s^(2) .

At what height above the surface of the earth will the acceleration due to gravity be 25% of its value on the surface of the earth ? Assume that the radius of the earth is 6400 km .

The acceleration of a body due to the attraction of the earth (radius R) at a distance 2R form the surface of the earth is (g=acceleration due to gravity at the surface of the earth)