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The escape speed of a body on the earth'...

The escape speed of a body on the earth's surface is 11.2 km `s^(-1)`. A body is projected with thrice of this speed. The speed of the body when it escapes the gravitational pull of earth is

Text Solution

Verified by Experts

The correct Answer is:
`31.68 xx 10^(3) ms^(-1)`
`v_(1) = 3v_(1) `. V is the escape velocity . `( 1//2) mv_(1)^(2) + ( - ( GMm)/( r )) = ( 1//2) mv_(2)^(2) + 0, v_(2) = sqrt( 8 ) xxv = sqrt( 8) xx 11.2 xx 10^(3) = 31.68 xx 10^(3) ms^(-1)`
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Knowledge Check

  • The escape speed of a body on the earth's surface is 11.2kms^(-1) . A body is projected with thrice of this speed. The speed of the body when it escape the gravitational pull of earth is

    A
    `11.2 kms^(-1)`
    B
    `22.4sqrt(2) kms^(-1)`
    C
    `(22.4)/(sqrt(2)) kms^(-1)`
    D
    `22.4sqrt(3) km s^(-1)`

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