Jupiter has a mass 318 times that of earth, and its radius is 11.2 times the earth's radius Estimate the escape velocity of a body from Jupiter's surface, given that the escape velocity from the earth's surface `11.2 kms^(-1)`.

Answer

`59.68 xx 10^(3) ms^(-1)`

Explanation

`v_(J) = sqrt( Gxx 318 M_(e ) // 11.2 R_(e )) = sqrt( 318 //11.2) xxv_(e ) = 59.68 xx 10^(3) ms^(-1)`