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With what velocity a body of mass m be p...

With what velocity a body of mass m be projected vertically upwards so that it may be able to reach a height nR above earth's surface

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To find the velocity with which a body of mass \( m \) must be projected vertically upwards to reach a height \( nR \) above the Earth's surface, we can use the principle of conservation of energy. Here’s a step-by-step solution: ### Step 1: Understand the Conservation of Energy The conservation of energy states that the total mechanical energy (kinetic energy + potential energy) of the body remains constant if only conservative forces are acting on it. ### Step 2: Write the Energy Equation The initial total energy (at the Earth's surface) can be expressed as: \[ E_i = U_i + K_i \] Where: - \( U_i \) = Initial Potential Energy = \(-\frac{GMm}{R}\) - \( K_i \) = Initial Kinetic Energy = \(\frac{1}{2}mv^2\) The final total energy (at height \( nR \)) can be expressed as: \[ E_f = U_f + K_f \] Where: - \( U_f \) = Final Potential Energy = \(-\frac{GMm}{R + nR} = -\frac{GMm}{(1+n)R}\) - \( K_f \) = Final Kinetic Energy = \(0\) (since the body comes to rest at the maximum height) ### Step 3: Set Up the Energy Conservation Equation According to the conservation of energy: \[ E_i = E_f \] Substituting the expressions for \( E_i \) and \( E_f \): \[ -\frac{GMm}{R} + \frac{1}{2}mv^2 = -\frac{GMm}{(1+n)R} \] ### Step 4: Rearranging the Equation Rearranging gives: \[ \frac{1}{2}mv^2 = -\frac{GMm}{(1+n)R} + \frac{GMm}{R} \] Factoring out \( GMm \): \[ \frac{1}{2}mv^2 = GMm\left(\frac{1}{R} - \frac{1}{(1+n)R}\right) \] \[ \frac{1}{2}mv^2 = GMm\left(\frac{(1+n) - 1}{(1+n)R}\right) \] \[ \frac{1}{2}mv^2 = \frac{GMmn}{(1+n)R} \] ### Step 5: Solve for \( v^2 \) Dividing both sides by \( m \) and multiplying by 2: \[ v^2 = \frac{2GMn}{(1+n)R} \] ### Step 6: Substitute \( g \) Using the relation \( g = \frac{GM}{R^2} \), we can rewrite \( GM \) as \( gR^2 \): \[ v^2 = \frac{2gRn}{(1+n)} \] ### Step 7: Take the Square Root Taking the square root gives: \[ v = \sqrt{\frac{2gRn}{(1+n)}} \] ### Final Answer Thus, the velocity \( v \) with which the body must be projected is: \[ v = \sqrt{\frac{2gRn}{(1+n)}} \]

To find the velocity with which a body of mass \( m \) must be projected vertically upwards to reach a height \( nR \) above the Earth's surface, we can use the principle of conservation of energy. Here’s a step-by-step solution: ### Step 1: Understand the Conservation of Energy The conservation of energy states that the total mechanical energy (kinetic energy + potential energy) of the body remains constant if only conservative forces are acting on it. ### Step 2: Write the Energy Equation The initial total energy (at the Earth's surface) can be expressed as: \[ ...
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