A spaceship is launched into a circular orbit close to the earth's surface . What additional velocity has now to be imparted to the spaceship in the orbit to overcome the gravitational pull. Radius of earth `= 6400 km`, `g = 9.8m//s^(2)`.

Answer

`3.28 xx 10^(3) ms^(-1)`

Explanation

Additional velocity `=v_(e ) - v_(0) = 0.414 xx sqrt( gR^(2) //R + h) ,h=0, v_(e ) - v_(0) = 0.414 sqrt( gR) = 3.28 xx 10^(3) ms^(-1)`