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45 g fo ethylene glycol (C(2)H(6)O(2)) i...

45 g fo ethylene glycol `(C_(2)H_(6)O_(2))` is mixed with 600 g of water. Calculate (a) the freezing point depression and (b). The freezing point of the solution.

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The correct Answer is:
(a) 2.25 K (b) 270.90 K
(a) `K_(f) =1.86^(@)"C mol"^(-1)`, weight of ethylene glycol `(C_(2)H_(6)O_(2))=45g`
Gram mol. wt. of ethylene glycol`=12xx2+1xx6+16xx2=62"g mol"^(-1)`
`DeltaT_(f)=K_(f) xx m`
`=(1.86xx "Weight of ethylene glycol" xx 100)/("Gram mol. wt. of ethylene glycol" xx "Weight of water")`
`=(1.86xx45xx1000)/(62xx600)=2.25K`
(b) Freezing point of solution `=273.15-2.25=270.90K`
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