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underset(x to 0)"Lt" ((1-e^(x))sin x)/(x...

`underset(x to 0)"Lt" ((1-e^(x))sin x)/(x^(2)+x^(3))=`

A

`-1`

B

0

C

1

D

2

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The correct Answer is:
A
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AAKASH SERIES-LIMITS-EXERCISE-II
  1. The equadratic equation whose roots are l and m, where l = lim( th...

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  2. Lt(x to 0) (tan^(3)x-sin^(3)x)/(x^(5))=

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  3. underset(x to 0)"Lt" ((1-e^(x))sin x)/(x^(2)+x^(3))=

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  4. Lt(x to 1) (ax^(2)+bx+c)/(x-1)=0, then

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  5. Lt(x to 0) (a sin x-sinx2x)/(tan^(3)x) is finite, then a=

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  6. Lt(x to 0) ((cos4x+a cos 3x+b)/(x^(4))) is finite then the values of a...

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  7. Lim(x to 0) (a.e^(x)-b)/(x)=2, then a,b are

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  8. Lt(x to 0) (a- sqrt(a^(2)-x^(2))-(x^(2))/(4))/(x^(4)),a gt 0. If L si ...

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  9. Lt(x to oo) ((x+1)^(10)+(x+2)^(1)....+(x+50)^(10))/(x^(10)-10^(10))

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  10. underset(x to oo)lim (sqrt(x^(2)+1)-root3(x^(2)+1))/(root4(x^(4)+1)-ro...

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  11. Lt(x to oo) (sqrt(x))/(sqrt(x+sqrt(x+sqrt(x))))=

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  12. Lt(x to oo)(sum n)/(1-n^(2))=

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  13. underset(n to oo)lim (n(1^(3)+2^(3)+...+n^(3))^(2))/((1^(2)+2^(2)+...+...

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  14. underset(n to oo)lim (1+3+5+....+(2n-1))/(2+4+6+..2n)

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  15. underset(n to oo)lim (1+3+3^(2)+...3^(n))/(1+2+2^(2)+...+2^(n))=

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  16. Lt(x to oo) (1+(1)/(3)+(1)/(9)+.....+(1)/(3^(n)))/(1+(1)/(5)+(1)/(25)+...

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  17. underset(n to oo)lim (1+3+6+...+n(n+1)//2)/(n^(3))=

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  18. Lt(x to oo)[(1)/(n^(2)-1)+(2)/(n^(2)-1)+....+(n)/(n^(2)-1)]=

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  19. If 0lt x lt y then Lt(x to oo) (y^(n)+x^(n))^(1//n)=

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  20. Lt(x to oo) (3.2^(n+1)-4.5^(n+1))/(5.2^(n)+7.5^(n))=

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