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AAKASH SERIES-LIMITS-EXERCISE-II
- Lt(x to (pi)/(2)) (sin x)^(tanx)=
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- Lt(x to 0)(e^(2x)+x)^(1//x)=
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- Lt(x to 1)(log(5)5x)^(log(x)5)=
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- Lt(x to a)((sinx)/(sina))^((1)/(x-a))=
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- Lt(x to0) ((x)/(sinx))^((cosx)/("x cosec"x-1)=
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- lim(xrarr0)[tan(x+(pi)/(4))]^(1//x) is equal to
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- Lt(x to 0)(cos((x)/(n)))^(n^(2))=
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- Lt(x to oo) ((x^(2)+x+3)/(x^(2)-x+2))^(x)=
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- Lt(x to oo) ((x+h)/(x-h))^(x)=4 then h=
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- If Lt(x to0) (1+ax)^(b//x)=e^(4), where 'a' and 'b'a re different nati...
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- If Lim(x to0) [1+x+(f(x))/(x)]^(1//x)=e^(3), then f(x) is
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- underset(x to 0)"Lt" ((1^(x)+2^(x)+3^(x)+....+n^(x))/(n))^(1//x))
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- Lt(x to 0) ((2^(x)+2^(2x)+2^(3x))/(3))^(1//x)=
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- Lt(x to oo) ((a(1)^((1)/(x))+a(1)^((1)/(x))+....+a(n)^((1)/(x)))/(n))(...
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- Lt(x to oo) ((a^((1)/(x))+b^((1)/(x))+c^((1)/(x)))/(3))^(x) when a,b,c...
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- Observe the following lists : The correct match is
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- Lt(x to0) ((|x|)/(x)+x+2)=
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- Lt(x to0)(sinx^(2))/(|x|)=
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- Lt(x to0)(1)/(x)=
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- Lt(x to 0) (1)/(2) (sqrt(1-cos2x))/(x)=
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