Lt(x to 0)x"sin"(1)/(x)=...

`Lt_(x to 0)x"sin"(1)/(x)=`

`oo`

cannot be determined

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The correct Answer is:

LIMITS
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INVERSET TRIGONOMETRIC FUNCTIONS
AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL-II PRACTICE SHEET (ADVANCED) INTEGER TYPE QUESTIOS)|5 Videos
LOCUS
AAKASH SERIES|Exercise PRACTICE EXERCISE|37 Videos

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Lt(x to oo)(cossqrt(x+1)-cos sqrt(x))=
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Lt(x to 0)x"sin"(1)/(x)=
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Lt(x to oo)x cos ((pi)/(4x))sin((pi)/(4x))=
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Lt(x to 0)((tanx)/(x))^((1)/(x^(2)))=
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Lt(x to 0)((sinx)/(x))^((sinx)/(x-sinx))=
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underset(x to 1)"Lt" (log(2) 2x)^(log(x)5=
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underset(x to 0)"Lt" ((1+tan x)/(1+sin x))^("cosec x")=
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Lt(x to oo)((x^(2)+ax+b)/(x^(2)+bx+d))^(x+k)=
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Lt(x to oo)((2x^(2)+3)/(2x^(2)+5))^(8x^(2)+3)=
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Lt(x to oo) ((x^(2)+5x+3)/(x^(2)+x+2))=
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If a,b,c,d are positive real numbers then underset(n to oo)"Lt" (1+(1)...
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Lt(x to 0)(1+tan^(2) sqrt(x))^(1//2x)
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Lt(x to 0)(cosx+sinx)^(1//x)=
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underset(x to 0)"Lt" ((16^(x)+9^(x))/(2))^(1//x)=
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Lt(x to oo)((2^((1)/(x))+27^((1)/(x))+8^((1)/(x)))/(3))^(x)=
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Lt(x to 0)((2^(x)+3^(x)+8^(x)+27^(x))/(4))^((1)/(sinx))=
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Lt(x to oo)(1-(7)/(x))^(3x)=
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Lt(x to oo)(1+(3)/(x))^(x//2)=
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for x in R,Lt(x to oo)((x-3)/(x+2))^(x)=
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