underset(x to 3-)"Lt" (|x-3|)/(x-3)=...

`underset(x to 3-)"Lt" (|x-3|)/(x-3)=`

A

0

B

1

C

`-1`

D

does not exist

Text Solution

Verified by Experts

The correct Answer is:

C

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AAKASH SERIES-LIMITS-PRACTICE EXERCISE

Lt(x to 0)(|x|)/(x)=
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Assertion (A) : Lt(x to 0)(|x|)/(x)=1 Reason (R) : Limit of a functi...
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underset(x to 3-)"Lt" (|x-3|)/(x-3)=
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underset(x to 1)"Lt" (x^(2)-1)/(|x-1|=
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Lt(x to 0)(sinx)/(|x|)=
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Lt(x to 0)(sin|x|)/(|x|)=
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Lt(x to 2) sqrt(4-x^(2))=
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Lt(x to 2-){[x]-x}=
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If f(x)=[2x], then
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Lt(x to 0^(+))(3|x|+x)/(5|x|-3x)=
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underset(x to 0-)"Lt" (5|x|+2x)/(7|x|-3x)=
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Lt(x to 5^(+)){x-[x]}=
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Lt(x to 0) sqrt(|x|-x)=
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Statement-I : Lt(x to 0) ((Tan[e^(2)]x^(2)-Tan[-e^(2)]x^(2))/(sin^(2)x...
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If f(x)={{:((sin[x])/([x]),at[x]ne0),(0,at[x]=0):} then Lt(x to theta...
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Lt(x to0) (e^(1//x)-1)/(e^(1//x)+1)=
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Lt(x to 0)(x.e^((1)/(x)))/(1+e^((1)/(x)))=
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Lt(x to 0)(sinx)^(tanx)=
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Lt(x to (pi)/(2))(tanx)^(cosx)=
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Lt(x to 0)((1)/(x))^(1-cosx)=
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