Lt(x to 0)((1)/(x))^(1-cosx)=...

`Lt_(x to 0)((1)/(x))^(1-cosx)=`

A

e

B

`e//2`

C

1

D

0

Text Solution

Verified by Experts

The correct Answer is:

C

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AAKASH SERIES-LIMITS-PRACTICE EXERCISE

Lt(x to 0)(sinx)^(tanx)=
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Lt(x to (pi)/(2))(tanx)^(cosx)=
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Lt(x to 0)((1)/(x))^(1-cosx)=
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Lt(x to 0)log(2x)x=
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Lt(x to 0)(log(sinx)sin2x)=
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underset(x to oo)"Lt" ((x+6)/(x+1))^(x+4)=
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Lt(x to 0)(64)/(x^(4))(1-"cos"(x)/(2)-"cos"(x)/(4)+"cos"(x)/(2)."cos"(...
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Lt(x to (1)/(2)) (sin^(-1)x-(pi)/(6))/(2x-1)=
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If f(x)=x^(2), phi(a)=b^(2),f^(1)(a)=n phi^(1) and phi^(1)(a)=ne0, the...
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Let alpha and beta be the distinct roots of ax^(2)+bx+c=0," then "unde...
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Lt(x to 0)((1-cos2x)(3+cosx))/(x.tan4x)=
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If Deltax= |{:(e^(x),-1),(sinx-1,1):}| then Lt(x to 0)(Delta(x))/(x)=
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Lt(x to oo)(x^(n))/(e^(x))=0 for
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Lt(x to 0)(sin2x+a sinx)/(x^(3)) is finite then a=
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If underset(x to 0)"Lt" (x(1+a cos x)-b sin x)/(x^(3))=1" then "(a,b)...
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The integer 'n' is for which Lt(x to 0)((cosx-1)(cosx-e^(x)))/(x^(n)) ...
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If 0 lt r lt 1" then "underset(n to oo)"Lt" (a+ar+...+ar^(n-1))=
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underset(n to oo)lim (1+a+a^(2)+.....+a^(n-1))/(1+b+b^(2)+...+b^(n-1))...
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The values of constants a so that underset(x to oo)lim ((x^(2)+1)/(x...
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underset(x to 0)"Lt" {1/x-(log(1+x))/(x^(2))}=
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