Aluminium carbide reacts with water according to the following equation :
`Al_4C_3 + 12H_2O rarr 4Al(OH)_3 + 3CH_4`
What volume of methane at S.T.P. is obtained from 12 g of aluminium carbide ?
[Relative molecular weight of `Al_4C_3=144, Al(OH)_3 = 78`]

Explanation

To solve the problem of how much volume of methane (CH₄) is produced from 12 g of aluminium carbide (Al₄C₃) at standard temperature and pressure (STP), we can follow these steps:

### Step 1: Determine the number of moles of aluminium carbide (Al₄C₃)
The formula to calculate the number of moles is:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
Given:
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