What will be the vapour pressure of a solution containing 5 moles of sucrose `(C_(12)H_(22)O_(11))` in 1 kg of water, if the vapour pressure of pure water is `4*57` mm of Hg ? `[C = 12, H=1,0 = 16]`

Explanation

To find the vapor pressure of the solution containing 5 moles of sucrose in 1 kg of water, we can use Raoult's Law, which states that the vapor pressure of a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.

### Step-by-Step Solution:

1. **Determine the vapor pressure of pure water**:
- Given: Vapor pressure of pure water = 4.57 mm of Hg.

2. **Calculate the number of moles of water**:
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