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The slope of the line in the graph of lo...

The slope of the line in the graph of log k (k = rate constant) versus `1/T " is " - 5841`. Calcu late the activation energy of the reaction.

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To calculate the activation energy (E_A) of the reaction using the given slope of the line in the graph of log k versus 1/T, we can follow these steps: ### Step 1: Understand the Arrhenius Equation The Arrhenius equation in logarithmic form is given by: \[ \log k = \log A - \frac{E_A}{RT} \] Where: ...
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The rate of a reaction depends upon the temperature and is quantitatively expressed as k=Ae^((-Ea)/(RT) i) If a graph is plotted between log k and 1/T, write the expression for the slope of the reaction? ii) If at under different conditions E_(a1)andE_(a2) are the activation energy of two reactions. If E_(a1) = 40 J// "mol and" E_(a2) = 80 J//" mol" . Which of the two has a larger value of the rate constant?

ICSE-SAMPLE PAPER 2014-PART-II (SECTION -A)
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