`0*3605` g of a metal is deposited on the electrode by passing `1*2` amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal ?

Explanation

Given: weight .w. of the metal `= 0*3605 g`
Current `= 1.2 amp`.
Time `= 15 " min " = 15 xx 60 sec`.
Atomic weight of metal = 96
According to Faraday.s first law of electrolysis :
Electrochemical equivalent
`Z= w/(Ixxt)`
`=(0*3605)/(1*2 xx 15 xx 60) = 3*34 xx 10^(-4)g c^(-1)`
Valency `=("Atomic wt.")/("Equivalent wt.")`
`=96/(3*34 xx 10^(-4) xx 96500)=2*98~~3`
( `:. " Equivalent wt" =Zxx F` )
`:.` Valency of metal is 3.