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Calculate the emf of the following cell ...

Calculate the emf of the following cell reaction at 298 K:
`Mg(s) +Cu^(2+) (0.0001 M) to Mg^(2+) (0.001M) +Cu(s) `
The standard potential `(E^(Theta))` of the cell is 2.71 V.

Text Solution

Verified by Experts

`Mg_((S))+Cu^(2+)(0.0001M)rarrMg^(2+)(0.001M)+Cu`
(i) By Nernst equation the EMF of the cell at 298K is :
`E=E^(@)-(0.0591)/(2)log""([Mg^(2+)])/([Cu^(2+)])`
`=2.71-(0.0591)/(2)log""(0.001)/(0.0001)`
`=2.71-0.02955=2.68V`
Thus, the EMF of the cell is 2.68V
Thus, the EMF of the cell is 2.68V
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