A refrigerator converts 100 g of water at `20^(@)C` to ice at `-10^(@)C` in 35 minutes.
Calculate the average rate of heat extraction in terms of watts.
Given : Specific heat capacity of ice = `2.1Jg^(-1)""^(@)C^(-1)`
Specific heat capacity of water = `4.2Jg^(-1)""^(@)C^(-1)`
Specific Latent heat of fusion of ice = `336Jg^(-1)`

Explanation

To solve the problem of calculating the average rate of heat extraction by the refrigerator, we will follow these steps:

### Step 1: Calculate the heat extracted when cooling water from 20°C to 0°C

The formula to calculate the heat extracted (Q) when cooling a substance is given by:

\[ Q = m \cdot c \cdot \Delta T \]

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