The displacement of a body of mass 2kg varies as `S=t^(2)+2t` .Where S is in meters and t is in second.The work done by all the forces acting on the body during the time interval t=0 to t=3s is ?

The displacement of a body of mass 2 kg veries with time t as S = t^(2) + 2t , where S is in seconds. The work done by all the forces acting on the body during the time interval t = 2s to t = 4s is

A point mass of 0.5 kg is moving along x- axis as x=t^(2)+2t , where, x is in meters and t is in seconds. Find the work done (in J) by all the forces acting on the body during the time interval [0,2s] .

A particle of mass 3 kg is moving along x - axis and its position at time t is given by equation x=(2t^(2)+5)m . Work done by all the force acting on it in time interval t=0 to t=3s is

The position of a particle of mass 10kg moving along x- axis varies with time as x=2+t^(2) (x is in meter and t is in second).Then work done by net force from t=0 to till body attains velocity of 10m/s is ?

The displacement of an object of mass 3 kg is given by the relation S=(1)/(3)t^(2) , where t is time in seconds. If the work done by the net force on the object in 2 s is (p)/(q) joule, where p and q are smallest integer values, then what is the value of p+q ?

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .