Write the Nernst equation at 298 K for the electrode reaction
`2H^(+)(0.1M)+2e^(-)toH_(2)(g)`

Write Nernst equation for the electrode reaction: M^(n+) +n e^(-) to M(s)

Write the relation between K_(p)and K_(c) for the following reactions (i) N_(2)(g)+3H_(2)(g)hArr2H_(2)(g)+O_(2)(g) (ii) 2H_(2)O(g)hArr2H_(2)(g)+O_(2)(g)

Write Nernst equation for the following cell reaction : Zn"|"Zn^(2+)(aq)"||"Cu^(2+)(aq)"|"Cu(s)

Write the relation between k_p and K_c for the following reactions. (i) N_2(g) +3H_2(g) hArr 2NH_3(g) (ii) 2H_2O(g) hArr 2H_2(g) +O_2(g)

Mark the correct Nernst equation for the given cell. F_((s))|Fe^(2+)(0.001 M) ||H^(+)(1M) | H_(2(g)) ( 1 bar ) | Pt_((s)) is

Calculate the cell e.m.f. and DeltaG for the cell reaction at 298K for the cell. Zn(s) | Zn^(2+) (0.0004M) ||Cd^(2+) (0.2M)|Cd(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.763 V, E_(Cd^(+2)//Cd)^(@) = - 0.403 V at 298K . F = 96500 C mol^(-1) .

Calculated the equilibrium constant for the following reaction at 298K : 2H_(2)O(l) rarr 2H_(2)(g) +O_(2)(g) Delta_(f)G^(Theta) (H_(2)O) =- 237.2 kJ mol^(-1),R = 8.314 J mol^(-1) K^(-1)

Write the Nernst equation and EMF of the following cells at 298K : a. Mg(s)|Mg^(2+)(0.001M)||Cu^(2+)(0.0001M)|Cu(s) b. Fe(s)|Fe^(2+)(0.001M)||H^(o+)(1M)|H_(2)(g)(1 ba r)|Pt(s) c. Sn(s)|Sn^(2+)(0.050M)||H^(o+)(0.020M)|H_(2)(g)(1 ba r)|Pt(s) d. Pt(s)|Br_(2)(1)|Br^(-)(0.010M)||H^(o+)(0.030M)|H_(2)(g)(1 ba r)|Pt(s)

Write the relation between K_(p) " and " K_(c) for the reaction: N_(2)(g) +3H_(2) (g) hArr 2NH_(3)(g)

Given C_(("graphite"))+O_(2)(g)toCO_(2)(g), Delta_(r)H^(0)=-393.5kJ" "mol^(-1) H_(2)(g)=+(1)/(2)O_(2)(g)toH_(2)O(1), Delta_(r)H^(0)=-285.8" kJ "mol^(-1) CO_(2)(g)+2H_(2)O(1)toCH_(4)(g)+2O_(2)(g) , Delta_(r)H^(0)=+890.3kJ" "mol^(-1) Based on the above thermochemical equations, the value of Delta_(r)H^(0) at at 298 K for the reaction C_(("graphite"))+2H_(2)(g)toCH_(4)(g) will be: