In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

Explanation

In this case, Mass of the compound taken = 0.468g
Mass of `BaSO_(4)` obtained = 0.668g
`because 233g` of `BaSO_(4)` obtained = 0.668g
`because 233g` of `BaSO_(4)` contain sulphur= 32 g
`therefore 0.668g` of`BaSO_(4)` will contain sulphur `=(32)/(233) xx 0.668 = 0.0917g`
So, 0.0917g of sulphur is present in 0.468g of the compound.
`therefore` Percentage of sulphur in the given compound `= (0.0917)/(0.468) xx 100= 19.60`