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Comment on the spontaneity of a process ...

Comment on the spontaneity of a process when
`Delta H gt 0, T Delta S lt 0`

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To determine the spontaneity of a process when \( \Delta H > 0 \) and \( T \Delta S < 0 \), we can follow these steps: ### Step 1: Understand the Gibbs Free Energy Equation The spontaneity of a process can be assessed using the Gibbs free energy change (\( \Delta G \)), which is given by the equation: \[ \Delta G = \Delta H - T \Delta S \] Where: ...
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Comment on the spontaneity of a process when DeltaH gt 0, T DeltaS lt 0

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Discuss the effect of temperature on the spontaneity of a process when for the process both DeltaH and DeltaS are positive.

Discuss the effect of temperature on the spontaneity of a process when for the process both DeltaH and DeltaS are negative.

What is the status of a process when (i) Delta G lt 0 (ii) DeltaG = 0 (iii) DeltaG > 0 ? In which of the above cases, the process can be used for obtaining useful work?

For an irreversible process, DeltaS gt 0 .

Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. For the spontaneity of a reaction, which statement is true?

How does T DeltaS determine the spontaneity of process?

For a given reaction, Delta H = 35.5 kJ mol^(-1) and Delta S = 83.6 JK^(-1) mol(-1) . The reaction is spontaneous at : (Assume that Delta H and Delta S do not vary with temperature)

ICSE-SAMPLE QUESTION PAPER 03-Questions
  1. Define the term standard free energy change (Delta G^(@)). How is it r...

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  2. Comment on the spontaneity of a process when DeltaH lt 0, T Delta S ...

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  3. Comment on the spontaneity of a process when Delta H gt 0, T Delta S...

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  4. Comment on the spontaneity of a process when DeltaH gt 0, T Delta Sgt...

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  5. Comment on the spontaneity of a process when DeltaH lt 0, T Delta S ...

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  6. What is smog and how it is formed?

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  7. Define metamerism. What type of compounds do show it? Give an example.

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  8. Discuss the shape of the B Cl(3) molecules using VSEPR model .

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  9. On the basis of VSEPR theory, predict the shapes of the following mole...

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  10. Dicuss the shape of the following molecules using the VSEPR model: A...

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  11. Justify that the following reactions are redox reactions : CuO(s)+H(...

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  12. Justify that the following reactions are redox reactions : Fe(2)O(3)...

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  13. Justify that the following reactions are redox reactions : 4BCl(3)(g...

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  14. Write formulase for the following compounds : Mg(II) chloride

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  15. Write formulas for the following compounds : Nickel (II) sulphate

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  16. Write formulas for the following compounds : Tin (IV) oxide

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  17. Write formulas for the following compounds : Thallium (I) sulphate

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  18. Identify the substance oxidised and reduced, oxidising agent and reduc...

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  19. Calculate the oxidation number of sulphur , chromium and nitrogen in H...

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  20. Explain why A branched chain alkane possesses lower boiling point than...

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