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15 mL of a gaseous hydrocarbon was requi...

15 mL of a gaseous hydrocarbon was required for complete combustion in 357 mL of air (21% of oxygen by volume) and the gaseous products occupied 327 mL (all volumes being measured at NTP). What is the formula of the hydrocarbon?

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`C_(3)H_(8)`
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50 " mL of " a gaseous hydrocarbon A requried for complete combustion. 357 " mL of " air (21% oxygen by volume) and gaseous products occupied 327 mL (all volumes being measured at STP. The molecular formula of the hydrocarbon A is (a). C_2H_6 (b). C_2H_4 (c). C_3H_6 (d). C_3H_6

Fifteen milliliters of gaseous hydrocarbo (A) was required for complete combustion 357 ml of air (21 % oxygen by volume) and gaseous products occupied 327 ml (all volumes being measured at STP). The molecular formula of the hydrocarbon (A) is:

15mL of a gaseous hydrocarbon required for complete combustion, 357mL air contianing 21% oxygen by volume. The gaseous product occupied 327mL. If all the volumes are measured at STP. The molecular formula of hydrocarbon will be:

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