`5.22xx10^(-4)` mole of a gas containing `H_(2),O_(2)andN_(2)` exerted a pressure of 67.4 mm in a certain standard volume. The gas was passed over a hot platinum filament which combined `H_(2)andO_(2)` into `H_(2)O` which was frozen out. When the gas was returned to the same volume, the pressure was 14.3 mm. Extra oxygen was added to increase the pressure to 44.3 mm. The combustion was repeated, after which the pressure read 32.9. What was the mole fraction of `H_(2),O_(2)andN_(2)` in the gas sample?

Answer

0.638, 0.262, 0.1

Explanation

2 volumes of `H_(2)` combine with 1 vol. of `O_(2)`. In the first combustion `H_(2)` is in excess, while in the second one, `O_(2)` is in excess.