At `18^@C`, the volume occupied by the gas is 400 ml. To what temperature, it should be heated so that its volume gets doubled at constant pressure?

Explanation

`V_1`= 400 mL
`V_2`=2 x 400 = 800 mL
`T_1= 18^@C` = 18+273 K `T_2`= ?
`T_1`= 291 K
`T_2`= ?
From charles.s law
`V_1/T_1=V_2/T_2`
`400/291=800/T_2`
`T_2=(291xx800)/400`
`=582^@C`
The temperature at which volume of gas will be doubled =`582^@C`